Question

PLZ ANSWER QUESTION 7

Answer 1

mass of engine = 8000 kg

mass of wagon = 2000 kg

total no of wagon = 5

force exerted by the engine = 40,000 N

frictional force provided by the track = 5000 N

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Net accelerating force

= force exerted by the engine - frictional force provided by the track

= 40,000 -5000

= 35,000 N

Net accelerating force = 35 ,000 N

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Net accelerating force

= total mass of the train × acceleration

= ( mass of engine + 5 × mass of wagon ) × acceleration

=( 8000 + 5 × 2000 ) × Acceleration

= 18,000 × acceleration

Net accelerating force =18,000 × acceleration

35,000 = 18,000 × acceleration

$\rightarrow\mathtt{acceleration = \dfrac{35000}{18000} }$

$\rightarrow\mathtt{acceleration = 1.94 \frac{m}{ {s}^{2} } }$

acceleration of the train = 1.94 m /s²

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First we need to find the net acceleration of all the wagons

Net accelerating force =(5× mass of wagon )× acceleration '

35,000 = (5 × 2000 ) × acceleration '

$\rightarrow\mathtt{acceleration ' = \dfrac{35000}{10000} }$

$\rightarrow\mathtt{acceleration ' = 3.5 \frac{m}{ {s}^{2} } }$

acceleration of each wagon = 3.5 m / s²

We need to find the force of wagon 1 on wagon

2

force on wagon 2 = net force of all 4 wagons

Force on wagon 1 by wagon 2

= (4 × mass of wagon)× acceleration '

= ( 4 × 2000 ) × 3.5

= 8000 × 3.5

= 28 , 000 N

Force on wagon 1 by wagon 2 = 28 ,000 N