Math, asked by anjusree83, 1 year ago

plz answer question no 1

Attachments:

Answers

Answered by waqarsd
0

 \sqrt{2}  {x}^{2}  -  \frac{3}{ \sqrt{2} } x +  \frac{1}{ \sqrt{2} } = 0 \\ for \: nature \: of \: roots \: calculate delta \\ i.e \: for \: a {x}^{2}   + bx + c = 0 \\  {b}^{2}  - 4ac \\ if \: it \: is \: zero \: roots \: are \: real \: and \: equal \\ if \: it \: is \: less \: than \: zero \: roots \: are \: imaginary \:  \\ if \: it \: is \: greater \: than \: zero \: roots \: are \: real \: and \: distinct \\for \: a \: b \: c \:  <  < {real \: numbers} >  >  \\  now \: here \: \\  {b}^{2}  - 4ac = (  { (\frac{ - 3}{ \sqrt{2} } )}^{2}  - 4( \frac{1}{ \sqrt{2} } )( \sqrt{2} )) \\  =  \frac{1}{2}  > 0 \\  =  > roots \: are \: real \: and \: distinct
hope it helps
Similar questions