Question

plz answer question quick urgent ​

Answer 1

Answer:

Step-by-step explanation:

5x-4y+8=0,7x+6y-9=0

Comparing equation (1) with $a_1x+b_1+c_1=0$

and eq (2) with $a_2x+b_2y+c_2=0$,

we get $a_1=5,b_1=-4,c_1=8,a_2=7,b_2=6,c_2=-9$

$\frac{a_1}{a_2}=\frac{5}{7} ,\frac{b_1}{b_2}=\frac{-4}{6}=\frac{-2}{3}\\\\ \frac{c_1}{c_2}=\frac{8}{-9}=\frac{-8}{9}$

Since $\frac{a_1}{a_2}\neq \frac{b_1}{b_2}$ .

So have unique solution.

Therefore the lines that represent that represent the linear equations intersect at a point.

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Using these rules along with first, solve remaining.

$\frac{a_1}{a_2}= \frac{b_1}{b_2}=\frac{c_1}{c_2}$

Then we have infinite solutions.The lines that represent linear equations have infinite solutions.

$\frac{a_1}{a_2}= \frac{b_1}{b_2}\neq \frac{c_1}{c_2}$

Then  have no solution.Then lines represent the linear equations are parallel.

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Hope helps you...

Answer 2

Answer:

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