plz answer quickly
the answer should be 48.05m
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For last 6m distance travelled , s=6m
time=0.2s
initial velocity=?
a=g=9.8m/s2
s=ut+1/2at²
=6=u(0.2)+1/2 x 9.8 x0.2x0.2
6=0.2 u + 4.9 x 0.04
u=5.8/0.2
u=29m/s
For distance x, u=0m/s
v=29m/s [ because initial velocity will be final]
a=g=9.8m/s2
s= v²-u²/2a
=29²-0²/2x9.8
=29x29/19.6
s=42.5m
Total distance=42.5 +6=48.5 m
time=0.2s
initial velocity=?
a=g=9.8m/s2
s=ut+1/2at²
=6=u(0.2)+1/2 x 9.8 x0.2x0.2
6=0.2 u + 4.9 x 0.04
u=5.8/0.2
u=29m/s
For distance x, u=0m/s
v=29m/s [ because initial velocity will be final]
a=g=9.8m/s2
s= v²-u²/2a
=29²-0²/2x9.8
=29x29/19.6
s=42.5m
Total distance=42.5 +6=48.5 m
bhavana9924:
thanks very much rashmika
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