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[0010001111]... Hello User... [1001010101]
Here's your answer...
To factorize it, we first need to find one of it factors, which can be found by the remainder theorem.
I've already found it. Its x+1
We break the terms so that we can take x+1 common from them.
2x³ - x² - 5x - 2
= 2x³ + 2x² - 3x² - 3x - 2x - 2
= 2x²(x+1) - 3x(x+1) - 2(x+1)
= (x+1)(2x²-3x-2)
= (x+1)(2x² - 4x + x - 2)
= (x+1)[2x(x-2) + 1(x-2)]
= (x+1)(x-2)(2x+1)
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Here's your answer...
To factorize it, we first need to find one of it factors, which can be found by the remainder theorem.
I've already found it. Its x+1
We break the terms so that we can take x+1 common from them.
2x³ - x² - 5x - 2
= 2x³ + 2x² - 3x² - 3x - 2x - 2
= 2x²(x+1) - 3x(x+1) - 2(x+1)
= (x+1)(2x²-3x-2)
= (x+1)(2x² - 4x + x - 2)
= (x+1)[2x(x-2) + 1(x-2)]
= (x+1)(x-2)(2x+1)
[0110100101]... More questions detected... [010110011110]
//Bot UnknownDude is moving on to more queries
//This is your friendly neighbourhood UnknownDude
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