Question

Plz answer step by step

Answer 1

The displacement is given by the area under the velocity-time graph. In this case,
Total displacement is equal to {Area of triangle ABF + Area of rectangle BCGF + Area of rectangle CEIG + Area of triangle CDE}
Displacement=$( \frac{1}{2}\times2\times5)+(4\times5)+(4\times5)+ (\frac{1}{2}\times4\times5)=55m$