Question

plz answer step by step fast​

Answer 1

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$\large{☞}$$\dfrac{7}{3}$

$\large{☞}$$\dfrac{-28}{9}$

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Question 9:

Let the other number be x.

Given,

Sum of the two numbers = $\dfrac{-5}{3}$

According to question,

$x + \dfrac{ - 12}{3} = \dfrac{ - 5}{3}$

Transposing constant terms to RHS,

$x = \dfrac{ - 5}{3} + \dfrac{12}{3}$

Taking LCM and simplifying,

$x = \dfrac{ - 5 + 12}{3} \\ \\ x = \dfrac{7}{3}$

Question 10:

Let the other number be x.

Given,

Sum of the two numbers = $\dfrac{-23}{9}$

According to question,

$x + \dfrac{5}{9} = \dfrac{ - 23}{9}$

Transposing constant terms to RHS,

$x = \dfrac{ - 23}{9} - \dfrac{5}{9}$

Taking LCM and simplifying,

$x = \frac{ - 23 - 5}{9} \\ \\ x = \frac{ - 28}{9}$

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