Math, asked by salilshekhar22, 1 year ago

plz Answer the 15question it is of factorization

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Answered by sj0101
1
this help u bro keep it up
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sj0101: hope this is help u
Answered by siddhartharao77
7

15.

Method - 1:

Given Equation is 12(2x - 3y)^2 - 16(3y - 2x).

It can be written as,

= > 12(2x - 3y)^2 + 16(2x - 3y)

= > 4(2x - 3y)[3(2x - 3y) + 4]

= > 4(2x - 3y)(6x - 9y + 4)

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Method - 2:

Given Equation is 12(2x - 3y)^2 - 16(3y - 2x)

= > 12(4x^2 + 9y^2 - 12xy) - 48y - 32x

= > 48x^2 + 108y^2 - 144xy - 48y + 32x

= > 4(12x^2 + 27y^2 - 36xy - 12y + 8x)

= > 4(12x^2 +  27y^2 - 18xy - 18xy - 12y + 8x)

= > 4(12x^2 - 18xy - 18xy + 27y^2 + 8x - 12y)

= > 4(6x(2x - 3y) - 9y(2x - 3y) + 4(2x - 3y)

= > 4(2x - 3y)(6x - 9y + 4)



Hope this helps!


siddhartharao77: :-)
sj0101: ok
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