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Step-by-step explanation:
Given-----> Sinθ = a / ( b + c )
To prove -----> Cosθ = 2 √bc CosA/2 / ( b + c )
Solution----->
1) Plzzz see the attachment
2) First we find value of cosθ , we know that ,
Sin²θ + Cos²θ = 1
=> Cos²θ = 1 - Sin²θ
=> Cosθ = √( 1 - Sin²θ )
Putting Sinθ = a / ( b + c ) then , and using
2S = a + b + c and
Cos A / 2 = √ { s ( s - a ) } / bc we proved required result .
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