plz answer the 22 question
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3
Let the two parts be x and y.
= > x + y = 4500
= > x = 4500 - y ------ (1)
Given that 5% of the first part is equal to 10% of the second part.
= > 5% of x = 10% of y
= > 5x/100 = 10y/100
= > x/20 = y/10
= > (4500 - y)/20 = y/10
= > 10(4500 - y) = 20y
= > 45000 - 10y = 20y
= > 45000 = 30y
= > y = 1500.
Substitute y = 1200 in (1), we get
= > x = 4500 - y
= >x = 4500 - 1500
= > x = 3000.
Therefore, the two parts are 3000 and 1500.
Hope this helps!
Answered by
5
Let the first part is x,
So other part will be ( total - x ) that is ( 4500 - x)
According to the question :
5% of first part x = 10% of other part ( 4500 - x )
5% of x = 10% of ( 4500 - x )
Removing or multiply 100 from or on both respectively ,
= > 5x = 45000 - 10x
= > 5x + 10x = 45000
= > 15x = 45000
= > 15 × x = 15 × 3000
= > x = 3000
Hence,
Parts are :
First part = x = 3000
Second part = ( 4500 - x ) = ( 4500 - 3000 ) = 1500
So other part will be ( total - x ) that is ( 4500 - x)
According to the question :
5% of first part x = 10% of other part ( 4500 - x )
5% of x = 10% of ( 4500 - x )
Removing or multiply 100 from or on both respectively ,
= > 5x = 45000 - 10x
= > 5x + 10x = 45000
= > 15x = 45000
= > 15 × x = 15 × 3000
= > x = 3000
Hence,
Parts are :
First part = x = 3000
Second part = ( 4500 - x ) = ( 4500 - 3000 ) = 1500
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