plz answer the 3 question
Attachments:
Answers
Answered by
0
3.total number of outcomes = 25
prime numbers 1 to 25 = 2 , 3 , 5 , 7 , 11 , 13 , 17 , 19 , 23 .
possible number of outcomes = 9
probability of selected a prime number is 9/25
1.Total no. of outcomes are 6.
(1) even no.are 2 , 4 ,6
multiple of 3 are 3 , 6
possible no. of outcomes are 5
then probability of even no. and a multiple of 3 is 5/6
2. Total no. of outcomes are 4 (HH , HT , TH , TT).
(1) two heads
possible no. of outcomes is 1
then probability of two heads is 1/4.
(2) one head
possible no. of outcomes are 2 (HT , TH) .
then probability of one head is 2/4 = 1/2.
(3) at least one head
possible no. of outcomes are 3 ( HH , TH , HT ).
then probability of at least one head is 3/4.
(4) at most one head
possible no. of outcomes are 2 (HT , TH) .
THEN the probability of at most one head is 2/4 = 1/2.
pls mark as brainlist .....
if my answer helps you......
prime numbers 1 to 25 = 2 , 3 , 5 , 7 , 11 , 13 , 17 , 19 , 23 .
possible number of outcomes = 9
probability of selected a prime number is 9/25
1.Total no. of outcomes are 6.
(1) even no.are 2 , 4 ,6
multiple of 3 are 3 , 6
possible no. of outcomes are 5
then probability of even no. and a multiple of 3 is 5/6
2. Total no. of outcomes are 4 (HH , HT , TH , TT).
(1) two heads
possible no. of outcomes is 1
then probability of two heads is 1/4.
(2) one head
possible no. of outcomes are 2 (HT , TH) .
then probability of one head is 2/4 = 1/2.
(3) at least one head
possible no. of outcomes are 3 ( HH , TH , HT ).
then probability of at least one head is 3/4.
(4) at most one head
possible no. of outcomes are 2 (HT , TH) .
THEN the probability of at most one head is 2/4 = 1/2.
pls mark as brainlist .....
if my answer helps you......
renukadevidhanda63:
1 and 2 nd sum
Similar questions