Question

plz answer the above mentioned question ​

Answer 1

Answer:

sin#+cos#=/3

square on both sides,

(sin^2#+cos^2#+2sin#cos#)=3

sin#cos#=1.

tan#+cot#=sin#/cos#+cos#/sin#

=sin^2#+cos^2#/sin#cos#

=1/1

=1..

Answer 2

Answer:

LHS=RHS Hence it is proved