Plz answer the above question fast.
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P(x)=3x^2-1
Put value of X
If ans. Comes zero than it is a zeroes of p(x)
P(x)= 3 (-1/√3)^2 - 1
= (3 x1/3) -1
= 1-1=0
So, (-1/√3) is a zeroes of p(x)
P(x)= 3 (2/√3)^2 -1
= (3 x 4/3) -1
=4-1=3
So, (2/√3) is not a zeroes of p(x)
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