Question

plz answer the above question it's an emergency and plz don't spam or your answer will be reported​

Answer 1

Answer:

1.

$\frac{3 + \sqrt{5} }{3 - 4 \sqrt{5} } \times \frac{3 + 4 \sqrt{5} }{3 + 4 \sqrt{5} } = \frac{29 + 15 \sqrt{5} }{ - 72}$

2.

$\frac{5 + 2 \sqrt{3} }{7 + 4 \sqrt{3} } \times \frac{7 - 4 \sqrt{3} }{7 - 4 \sqrt{3} } = \frac{ - 37 - 6 \sqrt{3} }{1} = -(37 + 6 \sqrt{3} )$

3.

$\frac{ 6 }{ \sqrt{11} - 1} \times \frac{ \sqrt{11} + 1 }{ \sqrt{11} + 1} = \frac{6 + 6 \sqrt{11} }{10}$

4.

$\frac{ \sqrt{7} }{ \sqrt{7} - \sqrt{3} } \times \frac{ \sqrt{7} + \sqrt{3} }{ \sqrt{7} + \sqrt{3} } = \frac{7 + \sqrt{7} \times \sqrt{3} }{4}$

5.

$\frac{3}{ \sqrt{5} + \sqrt{3} } \times \frac{ \sqrt{5} - \sqrt{3} }{ \sqrt{5} - \sqrt{3} } = \frac{3 \sqrt{5} - 3 \sqrt{3} }{2}$

6.

$\frac{15}{3 \sqrt{2} + 2 \sqrt{3} } \times \frac{3 \sqrt{2} - 2 \sqrt{3} }{3 \sqrt{2} - 2 \sqrt{3} } = \frac{45 \sqrt{2} - 30 \sqrt{3} }{6}$