Math, asked by kirito78, 10 months ago

Plz answer the answer in the blue box

Attachments:

Answers

Answered by Yashbhoir25
0

Answer:

C)9

Step-by-step explanation:

Answered by sudiplal22
1

Answer:

A) 6

Step-by-step explanation:

given,

a+b+c = 6

1/a+1/b+1/c = 3/2

a(1/b+1/c)+b(1/a+1/c)+c(1/a+1/b) = a*(3/2-1/a)+b(3/2-1/b)+c(3/2-1c)

                                                = [a*(3a-2)/2a]+[b*(3a-2)/2b]+[c*(3c-2)/2c]

                                                = (3a-2 +3b -2   + 3c-  2)/2

                                                = [3(a+b+c)-6]/2

                                                = (3*6-6)/2

                                                = 6(3-1)*2

                                                = 6*2/2

                                                 = 6

DO MARK IT AS BRAINLIEST.

Similar questions