PLz answer the attchment fast
Answers
sum = 0
i = 0
print("Natural number from 1- 10")
while i < 10:
print(i)
sum = sum + i
i = i + 1
Print("sum of the 10 natural number")
print(sum)
NOTE: you did not mention the language so i wrote the code in python 3
Note:
Natural Numbers start from 1.
So a variable i (can take any identifier) should be initialized with 1.
‘Sum’ variable is taken to store the progressing addition of numbers continuously upto 10
===========
Language using: Python.
============
Program:
i = 1
Sum=0
// As we need sum of numbers upto 10
// Make sure to follow indentation
// Condition can also be written as i <=10
while i < 11:
print(i)
Sum=Sum+i
i = i + 1
// As i in while loop strikes 11, loop terminates.
Print(“Sum of first 10 natural numbers is”, Sum)
============
Output:
1
2
3
4
5
6
7
8
9
10
Sum of first 10 natural numbers is 55
=============
You can also input the values dynamically.
===========
Language: Java
============
Program:
public class A
{
public static void main( String[] rags)
{
i= 1;
Sum = 0;
while(i<=10)
{
System.out.println(i);
Sum=Sum+i;
}
System.out.println(“Sum of first 10 natural numbers is” + Sum);
}
}
=============
Output:
1
2
3
4
5
6
7
8
9
10
Sum of first 10 natural numbers is 55
=============
Indentation won’t be a problem in the compiling process, in java.