Question

plz answer the following if the answer I'd correct I'll sure mark brainlliest ..

1) x= 2x²-3xy+4y² y=x²+2xy-3y² z=-4x²+5xy+y²
find the value of x+y+z

2) Factorize 3a⁴-18a²b²+3b⁴​

Answer 1

Step-by-step explanation:

1. (2x²-3xy+4y²) +(x²+2xy-3y²) +(-4x²+5xy+y)

(2x^2+x^2-4x^2)+(-3xy+2xy+5xy) +(4y^2-3y^2+y^2)

= -x^2+4xy+2y^2

2. 3a⁴-18a²b²+3b⁴

Taking out factors

3(a⁴-6a²b²+b⁴)

Hope this will help you...