Question

Plz answer the following question correctly.....《《no spamming 》》

Q : find the HCF of the following pair of integers and express it as a linear combination of them:
》 592 & 252 and 506 & 1155​

Answer 1

4=592m+252n where m=-20 and n=47

step by step explanations

592=252×2+89

252=88×2+76

88=76×1+12

76=12×6+4

12=4×3+0

Hence H.C.F=4

now

4=76-12×6

4=76-(88-76)×6

4=76×7-88×6

4=(252-88×2)×7-88×6

4=252×7-88×20

4=252×7-(592-252×2)×20

4=252×47+592×20

4=592m+252n

where m=-20 and n=47

Hence this is the required linear combination from

Answer 2

Answer:

plzz give me brainliest ans and plzzzz follow me