Question

Plz answer the following questions I'll mark ur answer as brainliest.
Question28,7,11 if u answer properly I'll mark it as brainliest

Answer 1

hello ,
here is your answers...

28. PV =nRT
R=0.082
P=700/760=0.921 ATM
T=273+27=300 K

0.921*20=n*0.082*300
n=0.748moles
1 mole contains 70grams
0.748moles contains 70*0.748/1=52.36.



7. when temperature is constant,then the
Boyle's law comes into play,
P1V1=P2V2

a. P1=760mm hg
V1=2L
V2=4dm^3=4L
P2=P1V1/V2 =380mm of hg

b. P1=760mm of hg
V1=2L
V2=(1 and a half times the initial
volume).
P2=(P1V1)/ V1/2=760*2*2/1=3040mm
of hg.

11. we have proved that P1=750mm hg-
14mm hg
=736mm hg
V1=50 cm^3
T1=17°c=290K
P2=760mm hg. let the final volume V2=x cm^3
T2=0°c=270K
Applying the gas equation:

P1V1/T1 =P2V2/T2

736*50/290=760*x/273
x= (736*50*273)/(290*760)
x=45.58cm^3 =45.60cm^3

( ANSWERS )