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Given =angle Q=(4x-5)degree
Angle S=(3x+10)degree
Solution =Angle Q+Angle S=180 degree
(4x-5)degree +(3x+10)degree =180 degree [opposite angle of parallelogram]
=4x+3x-5+10 degree =180 degree
=7x+5=180 degree
=7x=180 - 5degree
=x=175/7 degree
=x=25degree
ANGLE Q=(4x-5)degree
= ( 4×25-5)degree
=100-5degree
=9 5degree
ANGLE S=(3x+10)degree
(3×25+10)degree
75+10 degree
=85 degree
Angle S=(3x+10)degree
Solution =Angle Q+Angle S=180 degree
(4x-5)degree +(3x+10)degree =180 degree [opposite angle of parallelogram]
=4x+3x-5+10 degree =180 degree
=7x+5=180 degree
=7x=180 - 5degree
=x=175/7 degree
=x=25degree
ANGLE Q=(4x-5)degree
= ( 4×25-5)degree
=100-5degree
=9 5degree
ANGLE S=(3x+10)degree
(3×25+10)degree
75+10 degree
=85 degree
zara1011:
tq
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