Question

Plz answer the numericals quick an object of size 14 cm is placed at 32 cm in front of a convex mirror of focal length 16cm. At what distance from the mirror should a screen be placed , so that a sharp focused image Can be obtained? Find the size and the nature of the image

Answer 1

u = -32 cm.

f = -16 cm.

h = 14 cm.

Now, 1/f = 1/v + 1/u

(-1/16) = 1/v + (-1/32)

1/v = -1/16 + 1/32

1/v = -1/32

v = -32cm.

So, the screen should be placed 32 cm away from the mirror at left side.......ans.

Now, Magnification (m) = -v/u

m = -32/32

m = -1

Now, because m = h'/ h

-1 = h'/14

h' = -14 cm.......

So the height of the image is same as the object. The negative sign shows that the image is inverted..........Ans.


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Answer 2

Hola...

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QUESTION:- an object of size 14 cm is placed at 32 cm in front of a convex mirror of focal length 16cm. At what distance from the mirror should a screen be placed , so that a sharp focused image Can be obtained? Find the size and the nature of the image

ANSWER:- given information

=> U= -32cm

=> f=-16cm

=> h=14cm

According to formula

1/f=1/v+1/u

=> -1/16=1/v+(1/-32)

=> 1/V=-1/16+1/32

=> 1/v=(-1/32)

V=-32cm

=> magnification = -V/u

m=-v/u

m=-32/32

m=-1

=> -1=h'/14

Therefore => h'=-14cm

Negative sign always shows INVERTED IMAGE

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