Question

plz answer the question....​

Answer 1

Answer:

from the question

p1=80K.Pa=81.04*10^8 atm , p2=100K.Pa=1.013*10^10atm

v1=10L=10*10^3ml ,     v2=20L=20*10^3ml

T1=240c=513K t2=?

according to ideal gas equation (p1v1)/t1 = (p2v2)/t2

t2=(p2v2t1)/p1v1

t2=(1.013×10^10×20×10^3×513)/(81.04×10^8×10×10^3)

t2=1282.5K

t2=(1282.5 - 273)°c

t2=1009.5°c

at 1009.5°c temperature gas would occupy 20L when pressure increases to 100K.Pa

Explanation:

Answer 2

Answer:

ur αnѕwєr íѕ ín pícturє hσpє ít hєlpѕ

ur αnѕwєr íѕ ín pícturє hσpє ít hєlpѕ mαч gσd вlєѕѕ u

ur αnѕwєr íѕ ín pícturє hσpє ít hєlpѕ mαч gσd вlєѕѕ u ___________@divu

ur αnѕwєr íѕ ín pícturє hσpє ít hєlpѕ mαч gσd вlєѕѕ u ___________@divu