Question

plz answer the question
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Answer 1

Let p(x) = x³+ax+b

Since, (x+3) and (x+2) are factors of p(x)

-3 and -2 are zeroes of p(x)

p(-3) = -27-3a+b = 0

-3a+b = 27

b = 27-3a --------(1)

p(-2) = -8-2a+b = 0

-2a+b = 8 -------(2)

Substituting (1) in (2)

-2a+27-3a = 8

-5a = 8-27 = -19

a = 19/5

b = 27-3×19/5 = (135-57)/5

b = 78/5

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Answer 2

Step-by-step explanation:

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