Question

plz answer the question ​

Answer 1

Answer:

( a/b + b/a + 1 ) ( a/b + b/a - 1 )

Step-by-step explanation:

Given-----> a² / b² + 1 + b² / a²

To find ------> Factors of given expression

Solution-------> ATQ,

a² / b² + 1 + b² / a²

=> ( a / b )² + 1 + ( b/ a )²

=> ( a / b )² + ( b/a )² + 1

We add and subtract 1 , in it

=> ( a / b )² + ( b / a )² + 1 + 1 - 1

=> ( a / b ) ² + ( b/a ) ² + 2 - 1

We know that , 2 = ( a/b ) ( b/a ) , putting it , we get

=> { ( a / b )² + ( b/a )² + 2 ( a/b ) ( b/a ) } - 1

Now , we know that ,

( p + q )² = p² + q² + 2pq , using it , we get ,

=> ( a/b + b/a )² - ( 1 )²

We know that ,

( p² - q² ) = ( p + q ) ( p - q ) , using it , we get,

=> ( a/b + b/a + 1 ) ( a/b + b/a - 1 )

Additional information------->

1) ( a - b )² = a² + b² - 2ab

2)

( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ca

3) ( a³ + b³ ) = ( a + b ) ( a² + b² - ab )

4) ( a³ - b³ ) = ( a - b ) ( a² + b² + ab )

Answer 2

Answer:

I hope it is helpful to you......