Question

Plz answer the question. ​

Answer 1

Answer:

$\sqrt{3 {x}^{2} + 1} + \frac{4}{ \sqrt{3 {x}^{2} + 1} } =5 \\ \frac{3 {x }^{2} + 1 + 4 }{ \sqrt{3 {x}^{2} + 1 } } = 5 \\ \frac{3 {x}^{2} + 5}{5} = \sqrt{3 {x}^{2} + 1 } \\ s.o.b.s \: we \: get \: \\ = \frac{ {( {3x}^{2} + 5) }^{2} }{25} = 3 {x}^{2} + 1 \\ = 9 {x}^{4} + 25 + 30 {x}^{2} = 75 {x}^{2} + 25 \\ = 75 {x}^{2} - 30 {x}^{2} - 9 { x}^{4} = 0 \\ = 45 {x}^{2} - 9 {x}^{4} = 0 \\ = 9 {x}^{2} (5 - {x}^{2} ) = 0 \\ 5 - {x}^{2} =0 \\ - {x}^{2} = - 5 \\ {x}^{2} = 5 \\ x = \sqrt{5}$