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Since AB = CD (equal chords) so, their distance from center must le equal So, OP = OQ Now, In APOQ (1) ZOPQ = 20QP (2) ZOPQ + Z0QP + ZPOQ = 180° =22OPQ + 150° = 180 ° = ZOPQ = 15° Also, P is midpoint of AB OP LAB = ZAPO = 90° Now, ZAPQ = ZAPO - ZOPQ = 90° - 15° = 75°
hope it helps you follow
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AO=QO
AB=QP
BO=PO
<AOB=POQ.
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