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As P.D. across each of the resistors connected in parallel is equal, P.D. across each of the resistors is 2V.
Now by applying Ohm's law (V=IR) for the three resistors,
1.
2 = i × 3
i = 2/3 A
2.
2 = i × 2
i = 1 A
3.
2 = i × 3
i = 2/3 A
Total/effective current flowing in the circuit-
2/3 + 1 + 2/3 = 7/3 A = 2.33 A
Now by applying Ohm's law (V=IR) for the three resistors,
1.
2 = i × 3
i = 2/3 A
2.
2 = i × 2
i = 1 A
3.
2 = i × 3
i = 2/3 A
Total/effective current flowing in the circuit-
2/3 + 1 + 2/3 = 7/3 A = 2.33 A
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