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4 ) take 2 ^28 common
that becomes 2^28 (7)
In denominator, take 2^29 common, it becomes 2^29 (5) = 2^28 (10)
Dividing numerator and denominator, the answer is 7/10
5) 1/ (1+x^(a-b) ) = x^b / (x ^a + x^b)
1/ (1+x^(b-a) ) = x^a / (x ^a + x^b)
Adding both, the numerator and denominator become equal. So, answer is 1
that becomes 2^28 (7)
In denominator, take 2^29 common, it becomes 2^29 (5) = 2^28 (10)
Dividing numerator and denominator, the answer is 7/10
5) 1/ (1+x^(a-b) ) = x^b / (x ^a + x^b)
1/ (1+x^(b-a) ) = x^a / (x ^a + x^b)
Adding both, the numerator and denominator become equal. So, answer is 1
rakhijain2004p75vj6:
i don't get the answer of first plz can you give me the answer in aper
paper
ok.. let me explain
just see numerator
take 2^28 common
numerator = 2^28 (1+2+2^2 ) = 2^28 (1+2+4) = 2^28 (7)
ok
is it clear?
ya
thank you so much
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