Question

Plz answer the question
Correct answer will be praised​

Answer 1

$\sf \dfrac{4z-3}{4}-3=\dfrac{5z-7}{3}-4z-1$

$\sf \implies\dfrac{4z-3-12}{4}=\dfrac{5z-7-12z-3}{3}$

$\sf \implies\dfrac{4z-15}{4}=\dfrac{-10-7z}{3}$

$\sf \implies\dfrac{12z-45}{12}=\dfrac{-40-28z}{12}$

$\sf \implies {12z-45}={-40-28z}$

$\sf \implies 12z+28z=-40+45$

$\sf \implies 40z=5$

$\sf \implies z=\dfrac{5}{40}$

$\sf \implies z=\dfrac{1}{8}$