plz answer the question correctly
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Step-by-step explanation:
tan^2 thita - 1/cos^2 thita = -1
tan^2 thita - sec^2 thita = -1 (a/c to identity sec^2 thita -tan^2 thita = 1)
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Answer:
LHS,
= tan²∅ - 1/cos²∅
= TAN²∅ - Sec²∅
= -1( sec²∅ - tan²∅) . [ take -1 common]
= -1 × 1
= -1 = RHS.
Step-by-step explanation:
FORMULA USED - sec²∅- tan²∅ = 1 .
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