Question

plz answer the question correctly​

Answer 1

when n=1,tn=(-1)^1.2019= -2019

when n=2, tn=(-1)^2.2019= 2019

common ratio:-

t2/t1=2019/-2019=-1

i hope it is helpful for u

Answer 2

AnswEr :

The nth term of the GP is :

$\sf \: T_n = ( - 1) {}^{n} \times 2019$

We have to find the common ratio

Putting n = 1,we would get the first term :

$\sf \: T_1 = ( - 1) {}^{1} \times 2019 = - 2019$

Putting n = 2,we would get the second term :

$\sf \: T_2 = {( - 1)}^{2}(2019) = 2019$

Now,

If r is the common ratio of the above GP

$\implies \: \sf \: r = \dfrac{T_2}{T_1} \\ \\ \sf \implies r = \cancel{ - \dfrac{2019}{2019} } \\ \\ \implies \: \boxed{ \boxed { \sf \: r = - 1}}$