Question

plz answer the question correctly​

Answer 1

Step-by-step explanation:

${\underline{{\text{Given}}}}$

$\cot \theta \: = \dfrac{b}{a}$

${\underline{{\text{To Find:}}}}$

$\dfrac{ \cos \theta + \sin \theta}{ \sin \theta - \cos \theta}$

${\underline{{\text{Solution:}}}}$

As We know,

$\cot \theta \: = \dfrac{ \cos \theta}{ \sin \theta }$

$\therefore \: \dfrac{ \cos \theta}{ \sin \theta } = \dfrac{b}{a} \\ \\ \text{[Applying componendo and dividendo ]}</p><p> \\ \\ \dfrac{ \cos \theta + \sin \theta }{ \sin \theta - \sin \theta } = \dfrac{b + a}{b - a}$

Hence, the required answer is $\dfrac{b + a}{b - a}$

${\underline{{\text{ Some Important Trigonometry Rule }}}}$

sinø . cosecø = 1

cosø . secø = 1

tanø . cotø = 1

sin²ø + cos²ø = 1

cosec²ø - cot² = 1

sec²ø - tan²ø = 1

Answer 2

Answer:

b/a..

Step-by-step explanation:

Method 1:

you can use componando and dividendo as in:

for example: a+b\a-b it can be written as a+b+a-b/a+b-a+b=2a/2b=a/b

similarly, cos α+ sin α/cos α-sin α

it would be equal to cos α/sin α=cot α=b/a

Method 2:

cot α=b/a i.e base/perpendicular

we can find hypoteneus by pythagorus thoerem hy=√a²+b²

we can write sin α=a/√a²+b²

and cos α=b/√a²+b²

substitute this you will get the answer...