plz answer the question correctly
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hope it helps you......
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Hey!!!
Here is your answer...
In triangle ABC
A+B+C = 180 (by angle sum property)
Dividing both sides by 2...
A/2 + (B+C/2)= 180/2
A/2 +(B+C/2) = 90
B+C/2=90 -A/2
Taking sin on both sides...
Sin (B+C/2) = sin (90- A/2)
We know that sin (90-∅) = cos ∅
So, sin (B+C/2) = cos A/2....
Hope it helps....
Please mark as brain liest answer...
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