Question

plz answer the question correctly​

Answer 1

${\underline{{\text{To Find:}}}}$

$\dfrac{ \cos \theta}{1 - \sin \theta } + \dfrac{1 - \sin \theta }{ \cos \theta} = 2 \sec \theta$

${\underline{{\text{Solution:}}}}$

See in the attachment.

${{\boxed{ \text{\blue{Some important trigonometry Rules}}}}}$

$sin \theta . cosec \theta = 1 \\ \\</p><p>\cos \theta. \sec\theta = 1\\ \\</p><p>\tan\theta . \cot\theta = 1\\ \\</p><p>\sin^2\theta+ \cos^2 \theta= 1 \\ \\</p><p>\cosec^2 \theta -\cot^2 \theta = 1 \\ \\</p><p>\sec^2 \theta - \tan^2 \theta = 1$