Question

plz answer the question correctly

find the roots of polynomial​

Answer 1

$\frac{x}{1} - \frac{1}{3x} = \frac{1}{6} \\ \\ \frac{3 {x}^{2} - 1}{3x} = \frac{1}{6} \\ \\ 2(3 {x}^{2} - 1) = x \\ \\ 6 {x}^{2} - x - 1 = 0 \\ \\ 6 {x}^{2} - 3x + 2x - 1 = 0 \\ \\ 3x(2x - 1) + 1(2x - 1) = 0 \\ \\ (3x + 1)(2x - 1) = 0$

Either,

2x - 1 = 0

2x = 1

x = 1/2

or,

3x + 1 = 0

3x = -1

x = -1/3