Question

plz answer the question I need your help


1.
Evaluate: (6-1-8-1-1+(2-1-3-1)-1​

Answer 1

Answer:

30

answer is 30

I think you are satisfied with this

Answer 2

Evaluate:

$\sf{~~~~~:\implies ( {6}^{ - 1} - {8}^{ - 1} )^{ - 1} + ( {2}^{ - 1} - {3}^{ - 1} ) ^{ - 1} }$

$\sf{~~~~~:\implies \left( \dfrac{1}{6} - \dfrac{1}{8} \right)^{ - 1} + \left( \dfrac{1}{2} - \dfrac{1}{3} \right)^{ - 1} }$

$\sf{~~~~~:\implies \left( \dfrac{4 - 3}{24} \right)^{ - 1} + \left( \dfrac{3 - 2}{6} \right) ^{ - 1} }$

$\sf{~~~~~:\implies \left( \dfrac{1}{24} \right)^{ - 1} + \left( \dfrac{1}{6} \right) ^{ - 1} }$

$\sf{~~~~~:\implies 24 + 6 }$

$\bf{~~~~~:\implies 30 }$

Laws of Exponents

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\sf \bigstar{a}^{m} \times {a}^{n} = {a}^{m + n} \: \: \: \: \: \: \: \: \: \: \sf \bigstar{a}^{m} \div {a}^{n} = {a}^{m - n} \\ \: \: \: \: \sf{\bigstar( {a}^{m} ) ^{n} = {a}^{mn} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bigstar a {}^{m} \times {n}^{m} = (ab) ^{m} } \: \: \: \:\\ \: \: \sf\bigstar{a}^{0} = 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ \: \: \: \: \: \: \: \: {\bigstar\frac{ {a}^{m} }{ {b}^{m} }= \left( \frac{a}{b} \right) ^{m} } \: \: \: \: \: \: \: \:\\\\\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$