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p(2)=2^3-p2^2+12
= 8-p4+12
=20-p4
p4 =20
p 20÷4=5
p=5
= 8-p4+12
=20-p4
p4 =20
p 20÷4=5
p=5
Answered by
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Given that (x-2) is a factor of the polynomial.
So x-2 = 0
or x = 2 is a zero of the polynomial
Now, use x=2 in the polynomial
x^3 - px^2 + 12 = 0
or 2^3 - p(2^2) + 12 = 0
or 8 - 4p + 12 = 0
or 20 - 4p = 0
or 4p = 20
or p = 20/4 = 5
Hence value of p is 5.
So x-2 = 0
or x = 2 is a zero of the polynomial
Now, use x=2 in the polynomial
x^3 - px^2 + 12 = 0
or 2^3 - p(2^2) + 12 = 0
or 8 - 4p + 12 = 0
or 20 - 4p = 0
or 4p = 20
or p = 20/4 = 5
Hence value of p is 5.
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