Question

Plz. answer the question in Km/Hr The distance between two places A and B is 300 metres. Rohan starts running from A towards B while Deepak starts running from B towards A. They meet after 4 minutes. Had Rohan doubled his speed and Deepak reduced his by 50%, they would have meet one minutes earlier. Find their respective speeds.

Answer 1

Answer:

Suppose the speed of Rohan and Deepak are x and y m/s. respectively.

When both Rohan and Deepak met after 4 minutes i.e. 60×4 = 240 seconds

Then distance travelled by Rohan = 240x

And distance travelled by Deepak = 240y

And distance between A and B =  300 m

So we have;

240x+240y = 300⇒4x+4y = 5 ...(i)

Now when Rohan doubled his speed i.e. 2x and Deepak reduces his speed by 50% i.e. y2; then they meet 1 minute earlier i.e. 3 minutes i.e. 180 seconds

Distance travelled by Rohan = 180×2x = 360x

And distance travelled by Deepak = 180×y2 = 90y

Then we have;

360x+90y = 300⇒36x+9y = 30 ...(ii)

Now multiplying (i) by 9 and then subtracting (ii) from (i) we get;

36x+36y−36x−9y = 45−30⇒27y = 15⇒y = 15/27 = 5/9

Then, form (ii) we have;

36x+9×59 = 30⇒36x+5 = 30⇒36x = 25⇒x = 25/36

Therefore the speed of Rohan is 25/36  m/s and the speed of Deepak is 5/9 m/s.

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