Question

plz answer the question in the attachment



Class 11th physics​

Answer 1

Answer:

The velocity and acceleration of the particle are $2\alpha t-4\alpha+\beta$ and $2\alpha$.

Explanation:

Given that,

$x = \alpha(t-2)^2+\beta(t-4)$.....(I)

The velocity is the first derivative of the position of the particle.

On differentiating equation (I)

$v=\dfrac{dx}{dt}=2\alpha t-4\alpha+\beta$.....(II)

The acceleration is the rate of change of the velocity of the particle.

On differentiating equation (II)

$a=\dfrac{dv}{dt}=2\alpha$

Hence, The velocity and acceleration of the particle are $2\alpha t-4\alpha+\beta$ and $2\alpha$.

Answer 2

Answer:

hope it helps uh.........