Question

plz answer the question ,it is of class 9​

Answer 1

Answer:

do home work by ur own all we should only say aa I am ur teacher

Answer 2

Step-by-step explanation:

1 :-

Given: Two circles are drawn on sides AB and AC of a △ABC as diameters. The circles intersects at D.

To prove: D lies on BC

Construction: Join A and D

Proof: ∠ADB = 90° (Angle in the semi-circle) ...(i)

and ∠ADC = 90° (Angle in the semi-circle) ...(ii)

Adding (i) and (ii), we get

∠ADB + ∠ADC = 90° + 90°

=> ∠ADB + ∠ADC = 180°

=> BDC is a straight line.

Hence, D lies On third side BC.