Question

Plz answer the question it is urgent

1+secA/secA=sin^2A/1-costa

Answer 1

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Solution

Answer 2

Step-by-step explanation:

(1 + secA)/secA

=> (1 + 1/cosA)/secA

=> (cosA + 1/cosA)/[1/cosA]

=> 1 + cosA

Rationalize it.

=> (1 + cosA) * (1 - cosA)/(1 - cosA)

=> (1 + cosA)(1 - cosA)/(1 - cosA)

=> (1 - cos^2A)/1 - cosA

=> sin^2A/1 - cosA

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