Question

Plz answer the question
it's urgent​

Answer 1

Answer:

-10

Step-by-step explanation:

This is the formula to find the distance between two points :-$values = (x1, y1) and (x2, y2) \\ \\ \sqrt{(x1-x2)^2+(y1-y2)^2}$

Applying values :-

LHS : x1 = 3 , y1 = -2 , x2 = 8 and y2 = x

RHS : 13

To find :-

Value of 'x'.

Solution :-

After applying the values :-

$\sqrt{(3-8)^2+((-2)-x)^2} = 13 \\\\ \sqrt{(5)^2+(-2-x)^2} = 13 \\\\ (5) + (-2 -x) = 13 \\ 5-2-x = 13 \\ 3-x = 13 \\ 3 = 13+x \\ 3-13 = x \\-10 = x$

Verifying :-

x = -10

$\sqrt{(3-8)^2+((-2)-(-10))^2} = 13 \\\\ \sqrt{(5)^2+(-2+10))^2} = 13 \\\\ \sqrt{(5)^2+(8)^2}=13 \\\\ (5) + (8) = 13 \\ 13=13$

LHS = RHS

Conclusion :-

Hence, the value of x is -10.