Chemistry, asked by gagan36187, 1 year ago

Plz answer the question no 6

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Answered by ask1198
2

K.E=

 \frac{1}{2} m {v}^{2}

3  \times  {10}^{ - 25}  =  \frac{1}{2}  \times 9.1 \times  {10}^{ - 31}  \times {v}^{2}

v =  \sqrt{ \frac{2 \times 3 \times {10}^{ - 25} }{9.1 \times  {10}^{ - 31} } }

v =  \sqrt{ \frac{6 \times {10}^{7} }{91} }

v =  \frac{2000 \sqrt{1365} }{91}


gagan36187: Thnx
Answered by jogdandsakshi
0

Plz use 1/2mv2 formula

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