Question

Plz answer the question.
Thq...​

Answer 1

answer :---

first of all .. given ..

(X+3) (X+4) (X+ 5)

X+ 3 = 0 = X = -3

X +4 = 0 = X = -4

X+ 5 = 0 = X = -5

when we multiply each equation we get polynomial ..

see my adjoining attachment ..

equation (X+3) (X+4) (X + 5) = 0

p(X) = ax^3 + bx^2 + Cx + d = 0

polynomial is p(X) = x ^ 3 + 12x ^ 2 + 47 X + 12 = 0

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