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Given
ABC is a triangle
∠A is a bisector
AB = AC
∠B = 72°
CD = 1 cm
To find = length of BD
In ΔADC & ΔADB
(s) AB = AC - (given)
(a) ∠BAD =∠CAD - (AD bisect angle A)
(S) AD = AD - (common)
∴the ΔADC ≈ ΔADB - (by sas rule)
∵CD = BD = 1 cm - (by CPCT)
HOPE IT HELP YOU
ABC is a triangle
∠A is a bisector
AB = AC
∠B = 72°
CD = 1 cm
To find = length of BD
In ΔADC & ΔADB
(s) AB = AC - (given)
(a) ∠BAD =∠CAD - (AD bisect angle A)
(S) AD = AD - (common)
∴the ΔADC ≈ ΔADB - (by sas rule)
∵CD = BD = 1 cm - (by CPCT)
HOPE IT HELP YOU
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