Question

plz answer the questions I will give you stars​

Answer 1

Answer:

Solution(1) :-

Which of the following are Polynomials?

${ \sf{(i)4 {x}^{2} + 6x - 2 \: \: }}$

It is a Polynomial. Because it contains both variable and constants.

${ \sf{(ii)7}}$

It is not a polynomial, It not containing any variables

${ \sf{(iii)2 {x}^{2} + \frac{3}{x} - 5 }}$

It is not a Polynomial, Because, here the variable is in denominator. So it contains negative Power

${ \sf{(iv) \sqrt{3} {x}^{2} + 5y}}$

it is a polynomial. Because it not containing any negative power.

${ \sf{(v) {y}^{2} - 9 }}$

It is a polynomial. It containing non - negative integral power

${ \sf{(vi)2 \sqrt{x - 4} }}$

it is not a polynomial. Because 1/2 is not a whole number.

${ \sf{(vii)2 {x}^{ - 3} + 3x - 7 }}$

It is not a polynomial. Because here the power is in negative

${ \sf{(viii)3 {x}^{x} + 2 }}$

i think it is not a polynomial. because x is not whole number

${ \sf{(ix)4 {x}^{ \frac{1}{2} } - 3 }}$

It is not a polynomial. Here the power is not whole number.

${ \sf{(x) \frac{3}{2}x - \frac{1}{4} }}$

It is a polynomial. because x has power in positive

${ \sf{(xi)0.07 {b}^{2} - 2.6b + 13.908}}$

It is also a polynomial. Because its power is whole number

_____________________

Solution (2):-

Find the degree of polynomials?

${ \sf{(i)6 {y}^{2} + {y}^{3} - y }}$

Degree of this polynomial is 3

${ \sf{(ii)8 {x}^{4} + 5 {x}^{3} {y}^{3} - {y}^{4} }}$

Degree of this polynomial is 6

${ \sf{(iii)7 {x}^{5} + 2 {x}^{2} {y}^{2} - 12}}$

Degree of this polynomial is 5

${ \sf{(iv)5}}$

Degree if this polynomial is 0

${ \sf{(v)5t - \sqrt{3} }}$

Degree of this polynomial is 1

${ \sf{(vi)3 {x}^{6} + 6 {y}^{3} + 7 }}$

Degree of this polynomial is 6

_________________

Solution (3):-

${ \sf{(i)5 {x}^{2} + x - 7}}$

This is a quadratic polynomial

${ \sf{(ii)x - {x}^{3} }}$

This is a Cubic Polynomial

${ \sf{(iii)x - 1}}$

This is a linear polynomial