Question

plz answer the three questions
(exponential equations)
plz answer my questions first.​

Answer 1

Answer:

(2)2

(5) 0.5

(8) 1

Step-by-step explanation:

$2) \\ {3}^{y + 2} \times {27}^{3 - y} = 2187 \\ \\ = > {3}^{y + 2} \times {( {3}^{3}) }^{3 - y} = {3}^{7} \\ \\ = > {3}^{y + 2} \times {3}^{9 - 3y} = {3}^{7} \\ \\ = > {3}^{11 - 2y} = {3}^{7} \\ \\ = > 11 - 2y = 7 \\ \\ = > 2y = 4 \\ \\ = > y = 2 \\ \\ \\ \\ 5) \\ 4 \times {2}^{x - 1} = {8}^{x} \\ \\ = > {2}^{2} \times {2}^{x - 1} =( {2}^{3} ) {}^{x} \\ \\ = > {2}^{x + 1} = {2}^{3x} \\ \\ = > x + 1 = 3x \\ \\ = > 2x = 1 \\ \\ = > x = \frac{1}{2} = 0.5 \\ \\ \\ \\ 8) \\ {2}^{3 - x} \times {4}^{2x - 1} = 16 \\ \\ = > {2}^{3 - x} \times {( {2}^{2}) }^{2x - 1} = {2}^{4} \\ \\ = > {2}^{3 - x} \times {2}^{4x - 2} = {2}^{4} \\ \\ = > {2}^{3x + 1} = {2}^{4} \\ \\ = > 3x + 1 = 4 \\ \\ = > 3x = 3 \\ \\ = > x = 1$

$formulae \\ \\ {a}^{x} \times {a}^{y} = {a}^{x + y} \\ \\ { ({a}^{x} })^{y} = {a}^{xy} \\ \\ if \: {a}^{x} = {a }^{ y} \\ = > x = y$

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