Plz answer these.......................
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1
hope this helps you .
(If possible please cross check )
(If possible please cross check )
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suhanisharma:
Yeah thanks :)
Answered by
3
given ,
external diameter of sphere = 24 cm
so, external radius of sphere = 12 cm
spherical shell is melted and recast in cylindrical shell shape which height is 10cm , diameter of shell is 8 cm .
hence ,
volume of spherical shell = volume of cylinder
4/3 pi. { (R^3 - r^3 } = pi. r "^2 .h
4/3 { (12)^3 - r^3 } =(8/2)^2 x 10
4/3 {1728- r^3 } = 160
1728 - r^3 = 160 x 3/4 = 120
r^3 = 1728 - 120
r^3 =1608 = 8 x 201
take cube root both side
r= (8 x 201)^1/3
=2 (201)^1/3
given (201)^1/3 = 5.9
use this
r= 2 x 5.9 = 11.8 cm
hence internal diameter = 2 x 11.8
= 23.6cm
external diameter of sphere = 24 cm
so, external radius of sphere = 12 cm
spherical shell is melted and recast in cylindrical shell shape which height is 10cm , diameter of shell is 8 cm .
hence ,
volume of spherical shell = volume of cylinder
4/3 pi. { (R^3 - r^3 } = pi. r "^2 .h
4/3 { (12)^3 - r^3 } =(8/2)^2 x 10
4/3 {1728- r^3 } = 160
1728 - r^3 = 160 x 3/4 = 120
r^3 = 1728 - 120
r^3 =1608 = 8 x 201
take cube root both side
r= (8 x 201)^1/3
=2 (201)^1/3
given (201)^1/3 = 5.9
use this
r= 2 x 5.9 = 11.8 cm
hence internal diameter = 2 x 11.8
= 23.6cm
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