Math, asked by SuzainShamim13, 10 months ago

plz answer these 2 questions
it's urgent......​

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Answers

Answered by ishwarsinghdhaliwal
1

Step-by-step explanation:

 \sqrt{ \frac{2 +  \sqrt{3} }{2 -  \sqrt{3} } }  \\  =  \sqrt{ \frac{2 + 1.73}{2 - 1.73} }  \\  =  \sqrt{ \frac{3.73}{0.27} }  \\  =  \sqrt{ \frac{373}{27} }  \\  =\sqrt{13.81} =3.71

Factorise: x²-y²+2x+1

=x²+2x+1-y²

=(x+1)²-y² => [x²+2x+1=(x+1)²]

= (x+1+y)(x+1-y)

=(x+y+1)(x-y+1)

Remember:

(a+b)²= a²+b²+2ab

a²-b²=(a+b)(a-b)

Answered by abcdefghi76
1

Answer:

Step-by-step explanation:

\begin{lgathered}\sqrt{ \frac{2 + \sqrt{3} }{2 - \sqrt{3} } } \\ = \sqrt{ \frac{2 + 1.73}{2 - 1.73} } \\ = \sqrt{ \frac{3.73}{0.27} } \\ = \sqrt{ \frac{373}{27} } \\ =\sqrt{13.81} =3.71\end{lgathered}2−32+3=2−1.732+1.73=0.273.73=27373=13.81=3.71

Factorise: x²-y²+2x+1

=x²+2x+1-y²

=(x+1)²-y² => [x²+2x+1=(x+1)²]

= (x+1+y)(x+1-y)

=(x+y+1)(x-y+1)

Remember:

(a+b)²= a²+b²+2ab

a²-b²=(a+b)(a-b)

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