Question

plz answer these.
and explain me

Answer 1

Given,
Initial velocity (u)=0m s^-1
Acceleration (a)=2m s^-2
Time (t)=10s
Since,
S=UT+at²/2
:. Putting value
S=0×10+2(10)²/2
→S=m
Also,
V²=U²+2as
:. putting value
V²=0²+2×2×100
→V²=400
→V=√400=20m s^-1
Now,
Distance=speed×time
:. Putting value
S=20×10
→S=200m
Now,
Initial velocity (u)=20m s^-1
Final velocity (v)=0m s^-1
Acceleration (a)=-4m s^-1
Since,
V²=u²+2as
:. Putting value
0²=20²+2×-4×s
→0=400-8s
→-400=-8s
→-400/-8=s
→50=s
:.Total distance=
→+200+50=350m